PROB1Quick check●○○○○new1 Counting and probabilityCan P(A)=0.3\mathbb{P}(A) = 0.3P(A)=0.3, P(B)=0.4\mathbb{P}(B) = 0.4P(B)=0.4, P(A∪B)=0.8\mathbb{P}(A\cup B) = 0.8P(A∪B)=0.8 with A,BA, BA,B disjoint?