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ALG2 · 1

Groups revisited

10 concepts · 23 questions

Generators, cyclic groups and their subgroups, dihedral and symmetric groups, direct products, and cosets.

Overview 1The plan of this section

We recall the group theory of year one and sharpen it for what follows.

  1. Generating sets (Def. 1.1) and the classification of cyclic groups (Thm 1.2) and their subgroups (Prop. 1.3).
  2. Dihedral groups by generators and relations (Prop. 1.4); conjugacy in SnS_n is cycle type (Prop. 1.5).
  3. Direct products (Def. 1.6) and when Cm×CnC_m\times C_n is cyclic (Prop. 1.7).
  4. Cosets as equivalence classes and the index (Prop. 1.8).

Generators, cyclic groups classified, DnD_n presentation, cycle type = conjugacy class, Cm×Cn≅CmnC_m\times C_n\cong C_{mn} iff coprime, index.

Definition 1.1Subgroup generated by a set

For S⊆GS\subseteq G, the subgroup generated by SS, ⟨S⟩\langle S\rangle, is the intersection of all subgroups containing SS; equivalently the set of finite products s1±1s2±1⋯sk±1s_1^{\pm1}s_2^{\pm1}\cdots s_k^{\pm1} with si∈Ss_i\in S. GG is cyclic if G=⟨g⟩G = \langle g\rangle for some gg.

⟨S⟩\langle S\rangle: smallest subgroup containing SS = all words in S±1S^{\pm1}.

Theorem 1.2Classification of cyclic groups

Every cyclic group is isomorphic to Z\mathbb{Z} (if infinite) or to Cn=Z/nZC_n = \mathbb{Z}/n\mathbb{Z} with n=∣G∣n = |G|. In Cn=⟨g⟩C_n = \langle g\rangle, ∣gk∣=ngcd⁡(n,k)|g^k| = \frac{n}{\gcd(n, k)}, so gkg^k generates CnC_n iff gcd⁡(n,k)=1\gcd(n, k) = 1; there are φ(n)\varphi(n) generators.

Cyclic ⇒ Z\mathbb Z or CnC_n. ∣gk∣=n/gcd⁡(n,k)|g^k| = n/\gcd(n, k); φ(n)\varphi(n) generators.

Proof

Proposition 1.3Subgroups of cyclic groups

Every subgroup of a cyclic group is cyclic. In CnC_n there is exactly one subgroup of each order d∣nd\mid n, namely ⟨gn/d⟩\langle g^{n/d}\rangle, and no others.

Subgroups of cyclic groups are cyclic; CnC_n has exactly one subgroup of each order dividing nn.

Proof

Proposition 1.4The dihedral group by generators and relations

DnD_n (symmetries of a regular nn-gon, n≥3n\ge3) has order 2n2n and is generated by a rotation rr of order nn and a reflection ss with srs−1=r−1srs^{-1} = r^{-1}. Every element is uniquely rkr^k or rksr^ks (0≤k<n0\le k < n), and every rksr^ks is a reflection (order 22).

Dn=⟨r,s∣rn=s2=e,srs=r−1⟩D_n = \langle r, s\mid r^n = s^2 = e, srs = r^{-1}\rangle; elements rkr^k, rksr^ks; all rksr^ks are reflections.

Proof

Proposition 1.5Conjugacy in Sₙ is cycle type

For σ,τ∈Sn\sigma, \tau\in S_n, τστ−1\tau\sigma\tau^{-1} is obtained from the cycle decomposition of σ\sigma by replacing each entry ii by τ(i)\tau(i). Hence two permutations are conjugate iff they have the same cycle type, and the conjugacy classes of SnS_n correspond to partitions of nn.

Conjugate in SnS_n ⇔ same cycle type; classes ↔ partitions of nn.

Proof

Definition 1.6Direct products

The direct product G×HG\times H is the set of pairs with (g,h)(g′,h′)=(gg′,hh′)(g, h)(g', h') = (gg', hh'). The order of (g,h)(g, h) is lcm⁡(∣g∣,∣h∣)\operatorname{lcm}(|g|, |h|). A group GG is the internal direct product of subgroups H,KH, K if H,KH, K commute elementwise, H∩K={e}H\cap K = \{e\} and HK=GHK = G; then G≅H×KG\cong H\times K.

G×HG\times H componentwise; ∣(g,h)∣=lcm⁡(∣g∣,∣h∣)|(g, h)| = \operatorname{lcm}(|g|, |h|). Internal: commuting, trivial intersection, HK=GHK = G.

Proposition 1.7When is a product of cyclic groups cyclic?

Cm×Cn≅CmnC_m\times C_n\cong C_{mn} iff gcd⁡(m,n)=1\gcd(m, n) = 1.

Cm×CnC_m\times C_n cyclic ⇔ gcd⁡(m,n)=1\gcd(m, n) = 1 (group form of the Chinese remainder theorem).

Proof

Proposition 1.8Cosets and the index

For H≤GH\le G, the relation g∼g′g\sim g' iff g−1g′∈Hg^{-1}g'\in H is an equivalence relation whose classes are the left cosets gHgH. All cosets have ∣H∣|H| elements, and the number of left cosets equals the number of right cosets: the index [G:H][G : H]. For finite GG, ∣G∣=[G:H]∣H∣|G| = [G : H]|H|, and [G:K]=[G:H][H:K][G : K] = [G : H][H : K] for K≤H≤GK\le H\le G.

Cosets = equivalence classes, all of size ∣H∣|H|; ∣G∣=[G:H]∣H∣|G| = [G : H]|H|; indices multiply in towers.

Proof

Check 1.9Check: identifying a small group

  • Count elements of each order: cyclic groups have φ(d)\varphi(d) elements of order dd.
  • Abelian or not? DnD_n (n≥3n\ge3) and SnS_n (n≥3n\ge3) are not.
  • Products: Cm×CnC_m\times C_n is cyclic iff coprime.
  • Use Lagrange to rule out subgroup orders, and cycle type for conjugacy in SnS_n.

Element orders, abelian?, coprimality, Lagrange, cycle types.