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NUM2 · 1

Errors and root finding

9 concepts · 22 questions

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NUM2Step●○○○○new1 Errors and root finding
Step 1 of 3 towards a full problem
The problem

Solve f(x)=x3−x−1=0f(x) = x^3 - x - 1 = 0 (root x∗≈1.3247x^*\approx1.3247). (a) Do two Newton steps from x0=1.5x_0 = 1.5. (b) Show g(x)=(x+1)1/3g(x) = (x + 1)^{1/3} gives a convergent fixed-point iteration on [1,2][1, 2]. (c) Compare the convergence rates.

Compute x1x_1.